Efficient way to get your IP address in shell scripts

Efficient way to get your IP address in shell scripts

Context: On *nix systems, one may get the IP address of the machine in a shell script this way:

ifconfig | grep 'inet' | grep -v '127.0.0.1' | cut -d: -f2 | awk '{print $1}'  

Or this way too:

ifconfig | grep 'inet' | grep -v '127.0.0.1' | awk '{print $2}' | sed 's/addr://'  

Question: Would there be a more straightforward, still portable, way to get the IP address for use in a shell script?

(my apologies to *BSD and Solaris users as the above command may not work; I could not test)

Answer by coder for Efficient way to get your IP address in shell scripts

you give direct interface thereby reducing one grep.

ifconfig eth0 | grep 'inet addr:' | cut -d: -f2 | awk '{print $1}'  

Answer by t0mm13b for Efficient way to get your IP address in shell scripts

Look here at the Beej's guide to networking to obtain the list of sockets using a simple C program to print out the IP addresses using getaddrinfo(...) call. This simple C Program can be used in part of the shell script to just print out the IP addresses available to stdout which would be easier to do then rely on the ifconfig if you want to remain portable as the output of ifconfig can vary.

Hope this helps, Best regards, Tom.

Answer by ghostdog74 for Efficient way to get your IP address in shell scripts

you can do it with just one awk command. No need to use too many pipes.

$ ifconfig | awk -F':' '/inet addr/&&!/127.0.0.1/{split($2,_," ");print _[1]}'  

Answer by David J Merritt for Efficient way to get your IP address in shell scripts

ifconfig | grep 'broadcast\|Bcast' | awk -F ' ' {'print $2'} | head -n 1 | sed -e 's/addr://g'

Answer by Gautham Shervegar for Efficient way to get your IP address in shell scripts

May be this could help.

 more /etc/hosts | grep `hostname` | awk '{print $1}'  

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