How to increment a date in a bash script
How to increment a date in a bash script
I have a bash script that takes an argument of a date (yyyy-mm-dd)
I convert it to seconds with
startdate="$(date -d"$1" +%s)";
What I need to do is iterate 8 times, each time incrementing the epoch date by 1 day and then displaying it in the format mm-dd-yyyy
Answer by Aleks-Daniel Jakimenko for How to increment a date in a bash script
startdate=$(date -d"$1" +%s) next=86400 # 86400 is one day for (( i=startdate; i < startdate + 8*next; i+=next )); do date -d"@$i" +%d-%m-%Y done
Answer by ceving for How to increment a date in a bash script
It is not that easy to increment days. Normally it is done by converting the Gregorian date into a Julian day number. Then you can increment the day. And after that you calculate the Gregorian date. Here is example code:
http://it.toolbox.com/wiki/index.php/Convert_a_date_to_a_Julian_day
http://it.toolbox.com/wiki/index.php/Convert_a_Julian_day_to_a_date
Answer by swdev for How to increment a date in a bash script
Use the date
command's ability to add days to existing dates.
The following:
DATE=2013-05-25 for i in {0..8} do NEXT_DATE=$(date +%m-%d-%Y -d "$DATE + $i day") echo "$NEXT_DATE" done
produces:
05-25-2013 05-26-2013 05-27-2013 05-28-2013 05-29-2013 05-30-2013 05-31-2013 06-01-2013 06-02-2013
Note, this works well in your case but other date formats such as yyyymmdd may need to include "UTC" in the date string (eg. date -ud "20130515 UTC + 1 day"
)
Answer by Bill Matsoukas for How to increment a date in a bash script
Just another way to increment or decrement days from today that's a bit more compact:
$ date %y%m%d ## show the current date $ 20150109 $ ## add a day: $ echo $(date %y%m%d -d "$(date) + 1 day") $ 20150110 $ ## Subtract a day: $ echo $(date %y%m%d -d "$(date) - 1 day") $ 20150108 $
Answer by Benoy G for How to increment a date in a bash script
Increment date in bash script and create folder structure based on Year, Month and Date to organize the large number of files from a command line output.
for m in {0..100} do folderdt=$(date -d "Aug 1 2014 + $m days" +'%Y/%m/%d') procdate=$(date -d "Aug 1 2014 + $m days" +'%Y.%m.%d') echo $folderdt mkdir -p $folderdt #chown : $folderdt -R cd $folderdt #commandline --process-date $procdate cd - done
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