Is it efficient to perform individual, nested if statements?

Is it efficient to perform individual, nested if statements?

I'm working on the following problem:

You are driving a little too fast, and a police officer stops you. Write code to compute the result, encoded as an int value: 0=no ticket, 1=small ticket, 2=big ticket. If speed is 60 or less, the result is 0. If speed is between 61 and 80 inclusive, the result is 1. If speed is 81 or more, the result is 2. Unless it is your birthday -- on that day, your speed can be 5 higher in all cases.

I came up with the following code:

def caught_speeding(speed, is_birthday):      if is_birthday == True:          if speed <= 65:              return 0          elif speed <= 85:              return 1          else:              return 2      else:          if speed <= 60:              return 0          elif speed <= 80:              return 1          else:              return 2  

I feel like checking each one individually is a bit inefficient, or is it ok?

Answer by utku.zih for Is it efficient to perform individual, nested if statements?

You gotta love the bisect module.

def caught_speeding(speed, is_birthday):      l=[60,80]      if is_birthday:          speed-=5      return bisect.bisect_left(l,speed)  

Answer by Stefan Arentz for Is it efficient to perform individual, nested if statements?

I have no problems with your code. It is readable and clear.

If you want to go for less lines then you can do something like this:

def caught_speeding(speed, is_birthday):      adjustment = 5 if is_birthday else 0      if speed <= 60 + adjustment:          return 0      elif speed <= 80 + adjustment:          return 1      else:          return 2  

Answer by Jochen Ritzel for Is it efficient to perform individual, nested if statements?

You can do this:

def caught_speeding(speed, is_birthday):        if is_birthday:          speed = speed - 5        if speed <= 60:          return 0      elif speed <= 80:          return 1      else:          return 2  

Doing is_birthday == True means you didn't quite get booleans yet ;-)

Answer by John Machin for Is it efficient to perform individual, nested if statements?

Assuming that speed is an integer, and that efficiency means speed of running, not speed of understanding:

>>> def t(speed, is_birthday):  ...     speed -= 5 * is_birthday  ...     return speed // 61 + speed // 81  ...  >>> for s in xrange(58, 87):  ...     print s, t(s, False), t(s, True)  ...  58 0 0  59 0 0  60 0 0  61 1 0  62 1 0  63 1 0  64 1 0  65 1 0  66 1 1  67 1 1  68 1 1  69 1 1  70 1 1  71 1 1  72 1 1  73 1 1  74 1 1  75 1 1  76 1 1  77 1 1  78 1 1  79 1 1  80 1 1  81 2 1  82 2 1  83 2 1  84 2 1  85 2 1  86 2 2  >>>  

Answer by dansalmo for Is it efficient to perform individual, nested if statements?

def caught_speeding(speed, is_birthday):      speed -= 5 * is_birthday      return 0 if speed < 61 else 2 if speed > 80 else 1  

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